测试中，该团队发现芒果可以直接感知这种光，并产生内部信号通路。perceive与produce构成动作上的先后关系。55.D。本文讲述了蓝光对芒果的影响，colored符合语境。第二节主题语境：人与自我一一做事本文是记叙文。文章讲述了第一份兼职给作者带来的收获。56.It。考查it的用法。设空处作形式主语，真正的主语是to start off,.故填It。57.patience。考查名词。设空处与practice一起作并列主语，应用名词。58.an。考查冠词。设空处表示泛指，且限定ice cream store,故填an。59.recommended。考查一般过去时。设空处表示的动作发生在过去，应用一般过去时。60.working。考查动词-ing形式。设空处作介词of的宾语，应用动词-ing形式。本句中learnthe ropes of sth意为“学做某事的程序”。61.frightened。考查形容词。设空处作表语，意为“害怕的”，故填frightened。62.Gradually。考查副词。设空处修饰整个句子，故填副词。63.myself。考查固定搭配。by oneself意为“独自”，符合语境。64.raises。考查名词复数。afew后接可数名词复数，raise在此处意为“加薪”。65.for。考查固定搭配。thankful for sth意为“感激某事”。

参考答案学生月人书所以g(x)mx=g(3),即7m一6<0，fa2-4(3-a)≥0，1a≥2或a≤-6，所以m<号，所以00，脚x=-受≥2，g(2)≥0，又因为m(x2-x十1)-6<0在x∈[1,3]上恒成立，fa2-4(3-a)≥0，a≥2或a≤-6，所以m<2-x+在x[1,3]上恒成立.6即-号≥2，可得a≤-4，7+a≥0，a≥-7.6令J-2-x+1∴.-7≤a≤-6，综上，实数a的取值范围是[一7,2].因为函数y2-x+166在[1,3]上的最小值为9，(3)令h(a)=xa+x2+3.(-)+当a∈[4,6]时，h(a)≥0恒成立.所以只需m<号即可。只音8甲计十：所以m的取值花国是(-0，号）】解得x≤-3-√6或x≥-3十√6.∴.实数x的取值范围是（一∞，-3一√6]U[一3十6，十∞）.例8[解析]由f(x)=x2+(m-4)x十4-2m第2章函数=(x一2)m十x2-4x+4,第6讲函数及其表示令g(m)=(x-2)m十x2-4x十4.【基础检测】由题意知在[一1,1]上，g(m)的值恒大于零g1)=(-2)X(-1)+2-4x+40,1.(1)×(2)×(3)/·(4)×2.[-3,6)1g(1)=(x-2)+x2-4x十4>0，3.[-3,0]U[2,3][1,5][1,2)U(4,5]解得x<1或x>3.4.D[解析]因为函数f(x)的定义域为[0,2]，故当x∈(-∞，1)U(3,十o∞)时，对任意的m∈[-1,1]，函数f(x)的所以0≤2x≤2，解得0≤x≤1，值恒大于零，所以函数f(2x)的定义域为{x|0≤x≤1.例9[解析]f(x)=x2-2x十3=(x-1)2+2,5.x2-1(x≥0)[解析]令1=√：，则≥0，x=2,所以f(t)=2-1(t当x∈[1,4]时，[f(x)]min=f1)=2,≥0)，所以f(x)=x2-1(x≥0).[g(x)]m=g(4)=2十m.6.5士1[解析]f1)=1X(1+4)=5.当a≥0时，由f(a)=a2+4a由题意得，[f(x)]mn>[g(x)门mx,=5得a=1;当a<0时，由f(a)=a2-4a=5得a=-1.则2>2+m.综上可知a=土1..m<0.【知识要点】例10[解析]当0≤x≤3时，[f(x)]m血=f(0)=0,1.非空数集任意唯一确定∫：A→B当1<<2时，[g(x]m-g(2)-}-m,2.(1)定义域函数值值域(2)定义域对应关系值域电题意得fxl≥[gx门m0≥号-m(3)解析法图象法列表法3.对应关系并集并集m>≥【关键能力】训练巩固例(1)B[解析]由集合M={x1-1≤x≤3)，N={y10≤y≤3)，7.[解析](1)，当x∈R时，x2+ax十3-a≥0恒成立，可排除A,D.由函数的定义知，每一个x只能对应唯一一个y,而C选项需△=a2-4(3-a)≤0，即a2+4a-12≤0，中当一1≤x<3时，每一个x都有两个y与之对应，不符合函数的定义，.实数a的取值范围是[-6,2].故排除C.(2)当x∈[-2,2]时，设g(x)=x2+a.x十3-a≥0，分如下三种情况讨(2)BC[解析]A.f(x)=x一1的定义域为R,论（如图所示）：g(x)=-1的定义域为(-o∞，0)U(0,十∞)，s(a)故f(x)≠g(x),A错误；/g(x)B.f(x)=log221=x,g(x)=故f(x)=g(x),B正确；20202C.f(x)=|x|,g(x)=x2,图1图2:|x|=√，且f(x)与g(x)定义域相同，∴f(x)=g(x),C正确；g()D.f(x)=nx2的定义域为(-o,0)U(0,十∞)，g(x)=2nx的定义域为(0，十∞)，故f(x)≠g(x),D错误。-202训练巩固1.C[解析]①函数y=2x十3的定义城为R,值域也为R,即定义城和图3①如图1，当g(x)的图象恒在x轴上方且满足条件时，值城相同；②函数y=上的定义城为(-∞，0)U(0,十c0),值城也为有△=a2-4(3-a)≤0，即-6≤a≤2.(一∞，0)U(0,十o),即定义域和值域相同；③指数函数y=2的定义②如图2，g(x)的图象与x轴有交点，城为R,值城为(0，十∞)，即定义城和值域不同；④幂函数y=x意的定义但当x∈[-2，+co)时，g(x)≥0，域为[0，十∞)，值域也为[0，十c∞)，即定义域和值域相同.故选C.4>0,x+1,-1≤x<0即x=-≤-2，2.f(x)=l-zz,0Kx≤2g(-2)≥0，[解析]由题图可知，当一1≤x<0时，f(x)=x十1；当0≤r≤2时，f(x)=-x507

第9章统计学生用书心训练巩固临界值表：6.某机构为了了解不同年龄的人对一款智能a0.050.010.001家电的评价，随机选取了50名购买该家电Ta3.8416.63510.828的消费者，让他们根据实际使用体验进行评分.(1)设消费者的年龄为x,对该款智能家电的评分为y.若根据统计数据，用最小二乘法得到y关于x的经验回归方程为y=1.2x十40，且年龄x的方差为s2=14.4,评分y的方差为s号=22.5.求y与x的相关系数r,并据此判断对该款智能家电的评分与年龄的相关性强弱.(2)按照一定的标准，将50名消费者的年龄划分为“青年”和“中老年”，评分划分为“好评”和“差评”，整理得到如下数据，请依据α=0.01的独立性检验，能否认为对该智能家电的评价与年龄有关联.评价年龄好评差评青年816中老年206附：经验回归直线y=x十a的斜率b=0相关系数r=2(x,-x0(0-),独立性检验中2x-2-n(ad-bc)2的t=a+a十c)6+d0c+D其中n=a+6+c+d.303

参考答滨学生月书x(0,2)2(2,+o∞)于S点，正三角形的边长为x>0,则0G=子×县x=侣f(x)+0f(x)元1n2-1￥故f(x)在定义域上的极大值为f(x)机大值=f(2)=1n2-1,无极小值.(2)由(1)知，函数f(x)的定义域为(0，十∞)，当a≤0时，f(x)>0在(0，十∞)上恒成立，则函数在(0，十∞)上单调递增，此时函数在定义域上无极值点；当>0时，若x(0,),则fe>0,若z(日，+），则f田)<0，s0==v50-远-√-得)-()√5(5-鼓通数在x=日处有板大值。三校维的体积V=号S0版·h=子×92×√5(5-号)=综上可知，当a≤0时，函数f(x)无极值点，当>0时，西数)=：)有-个报大值点，且为x=合8[解析](：f✉)=士+红-a(>0,设n)=5r-得，>0，则e=202-54,又f(x)在(0，十∞)上单调递增，令n(a)=0,即4x-号=0，得x=43,易知n(x)在x=45处取得最所以包有fx20,甲士十红-。≥0(>0)框底立，a<(+）√3大值.面叶上≥2√工=2，当且收当=1时取等号，所以a<2Vu=爱×48X5=4压，即函数f(x)在(0，十o∞)上为单调增函数时，a的取值范围是（一o∞，2]】3[解折]af)=+ar一a+D=a-D-卫(>0，2f)-fa)=lh妥+7(d-)-a-,①当a≤0时，ax-1<0,故当00,f(x)单调递增，当x>1时，f(x)<0,f(x)单调递减，此时f(x)在x=1处有极大值；又“fe)=}+红-a=-2出(a>0.x②当0a<1时，合>1，令f)=0,解得x=日=1所以x1,x2是方程x2一ax十1=0的两个实根，故当00,f(x)单调递增，由韦达定理得：x1十2=a,x1x2=1,当1K<日时，fx)<0,f)单将造藏，“fx)-fx)=n+是(-x)-a(-)当>是时，f:)>0,x)单调递增此时f(x)在x=1处有极大值；=n器-（贤-》③当a=1时，f(x)≥0，f(x)在定义域内单调递增，无极大值；④当>1时，甲0<日<1，令了x)=0,解得x=日=1.设=要，故当0<<日时，f:)>0,)单调逢增。令ae)=h-(:-）②0.当1时，∫(x)>0,f(x)单调递增，此时f(x)在x=1处有极小值综上所述，当a<1时，f(x)在x=1处有极大值，h(t)在[E,十∞)上是减函数，即a的取值范围是(-∞，1).a0<)=2(1-E+9),(2)由（可知，当0Ka<1时，M=fID.N=日），故)-a)曲最大值为号(1-+)】当1时，M=(日）N=f.B组题所以1M-N=(日）-f)1.C[解折]由题意可知，x1<00,所以-2+2=品十，则理-2西-十2-2，-(&-a-)-(-号-)令ux)=+2x-2>0且x≠1，ux>0,=血日-云+号@>0且a≠1011.①当00,②当x>1时，可知u(x)>0,4(x)=2nx2+lnx-1-(In z)2则g)=-士+2+=2+1-业0，2x22x22血-)也x+,令(x)=0,则=，=。（舍去），若11单调递增，<√e,则u'(x)<0,若x>√E,则'(x)>0,则x=√E时取得极小值u(W)于是|M-NI=lg(a)l,=4Ve-2,也为最小值，所以u(x)≥u(WE),即x2一2x1≥4Ve-2,所以所以M-N训=lg@)1在a=合或a=2处取得最大值，g(合)x2-21的最小值为4ve-2.故选C.是-h2,g21=是-ln2,32.4√5cm3[解析]如下图，连接DO交BC于点G,设D,E,F重合由于a>0且a≠1，lM-N|=g(a)川>g(1)=0,639

18.(12分)已知函数f(x)=log(x74)-log(a-x),且f(-1)=-1.(1)求f(x)的定义域要(2)求不等式f(2-x)≥f(2)的解集，查代0共，长，小共代0卧帕数茸，8食暗，代哥的反数喷全分的眼命直县中题命个四州杀要处不个的”男<骨要不代家面量式才式组”小道秋：州杀农京不要点的"一。县升茶要杀的"0=9“0=19.(12分)呗，同不家其目：同肤息宜床上的喷西民亲告已知数列{a的前n项和为S,且a,=1,2=an-n十1.凌函己S,门(1)求{an}的通项公式；县啦“装函煮同“益时来用(2)设6.=：求数列{b,的前n项和T20.(12分)民族要复兴，乡村要振兴，合作社助力乡村产业振兴，农民专业合作社已成为新型农业经营主体和现代农业建设的中坚力量，为实施乡村振兴战略做出了巨大的贡献.某农民专业合作社为某品牌服装进行代加工，已知代加工该品牌服装每年需投入固定成夺0万元，每代加分r+2,0长10工x万件该品牌服装，需另投人f(x)方，且f(x)=根据市14x+450115,10

八年级数学（北师大版）0000060006000000∠ADB=80°-x∴.PP'=AP=5,∠APP'=60°若∠BEC=∠ADB,在△BPP'中，则x°十40°=80°-x°，解得x°=20°，PP'=5,BP=12,BP'=13,在行移动AD的过程中，存在某种情况，..PP2+BP2=BP2,使∠BEC=∠ADB,此时∠ADB=60°，∴△BPP'为直角三角形，∠BPP=90°，专题训练（三）巧用移和旋转解决∴.∠APB=∠APP+∠BPP'=60°+90°=150°.点P与点P'之间的距离为5，∠APB的度数图形的变换问题为150°.1.C2.解：如图，将△A'OC沿A'A的方向移，移第四章因式分解的长度为A'A,得△AQR,将△BOC沿BB'方知识回顾向移，移的长度为BB,得△BPR.①积②相同③公因式④公因式⑤不改变⑥改变⑦a+b⑧+2ab⑨-2ab⑩0重点突破反馈训练1.D2.B3.b(a+5)(a-5)4.(x+1)(x-2).OP=OQ=2,∠POQ=60°，5.3(a+2)26.A7.B∴.连接PQ,则PQ=2.针对训练又QR+RP=OC+OC=CC=2.P,R,Q三，点共线.在等边三角形POQ中，1.D2.D3.D4.A5.B6.C7.B8.D9.A10.BSAAOB'十S△BPR+S△ROA11.m(m-2)=S△A0B+SAOc+S△oA'

、·8B=C∠EAB=30°，连接EC,4思路分析为什么作：要证△ACE是等腰三角形，没有与其相关的条件，第5题解图怎么作：∠ACB=90°，DE是⊙0的切线，∴.△AEB∽△ACD故连接OC.AE_AC_√3得到什么：△EC0△ACB.·ABAD-2:∠EAB=∠DAC=30°，∴、∠EAC=∠EAB+证明：如解图，连接OC.∠BAC=∠BAC+∠CAD=∠BAD..△EAC△BAD.ECAE√3BD AB 25AB=5BE=2AB三2第4题解图,∠EAB=30°，∠AEB=90°，∠ABC=30°，.DE与⊙O相切于点C,∴.OC⊥DE.∠EC0=∠ACB=90∴.∠EBA=60°..∠EBC=90°.·OF∥BC,即OE∥BC,∴.∠EOC=∠OCB..△EBC为直角三角形..OC=OB,∴.∠OCB=∠OBC在Rt△EBC中，EC=BE+BC=2,∴.∠EOC=∠OBC.∴.△ECO∽△ACB.6C紀、BD=2EC=133OC BC的3:∠ECO=∠ACB=90°，∴.∠ACE=∠BCO6.(1)∴.△ACE∽△BCO.思路分析,△BCO是等腰三角形为什么作：要证MF⊥CE,即∠FMC=∴.△ACE是等腰三角形90°，题于中无与∠FMC有关的角度，需5.思路分析要构造角进行等角转化，为什么作：要求BD的长，题于中无与BD怎么作：LECF=。LBCD,故连接AC.有关的线段长或特殊三角形，需要构造得到什么：△BMC△AFC.含BD的特殊三角形或与BD相似的特殊三角形进行转化求解，证明：如解图①，连接AC怎么作：∠ABC=30°，在Rt AACD中∠DAC=30°，故以AB为斜边作Rt△ABE,且∠EAB=30°，连接EC得到什么：△AEB一△ACD,△EACMABAD解：如解图，以AB为斜边作Rt△ABE,且第6题解图①万唯数理化QQ交流群：66843586045

BWhat does the underlined word "commenced"in Paragraph 4 mean?A\Stopped.B.StartedC AvoidedD.ChangedWhat does the authorACOVID-19 swant to show by mentioni some other European cities?spreads quickly across EuropeB.These cities als have many odondon improves its traffic by learning from themThese cities also take positive action toencourage cyeling.My husband and I visited KwaZulu-Natal years ago with friends.We sat around the firelistening to al the guests tell their tales.One of them happened to be an estate agent fromGraaff-ReinetHe talked about the Great-Karoo-telling tales of its historical significance,theamazing animals and the great beauty of the place.2On the spot,we agreed we would go and visit the area next time we were in South Africa(at the time we vwereliving in Paris).So,a few months later we did just that,and -stayed-overnighin the Drostdy Hotel in Graaff-Reinet with our two young children-that's when I remembered theKaroo of my childhood-dry and dusty with nothing in sight but tumbleweed (and theoccasional sheep.There was no way we were going-to buy one square inch of such a bare landseape.So we droveout to the first farm,Apieskloof,that we'd arranged to visit,and we just fell-in love.uned off the road and up into the mountains,the beauty of the place fully revealed itselfso unlikewhat I had always thought the Karoo to be like.We were taken by the place.4That was 20 years ago-we are celebrating our 20-year anniversary in November of this year.Wepurchased an additional ten farms to create what is Samara today.But we decided to open it upto the public in 2005 because we felt it needed to benefit society,not just ourselves.We got started inthe ecotourism business and today we are going from strength to strength.A.The grassland was green and richB.He started telling us about South Africa.The dream was reawakened and we bought the farm.D.It was a very emotional experience that brought us togetherWe started chatting with our neighbor at the next-door table.Originally,it was just a quiet and private place for the-family.CWe were attracted by the idea of returning the land to its former.greatness.There may be a new form of transport soon-flying taxis.Many of us grew upwatchingheNA and Joyti the Uing airis thatPeY-fi movies with these.Now science fiction is becoming science fact.(operate)at the Expo 2025 in Osaka.They need to work out whattaffic rules the taxislland what kind of)the pilots will need.The all-eleetric taxi with seats4five peoplecan fly as far as 241 kilomefers with a top speed of 321kph.每h以tJoby's CEO says the taxis are environmentally friendly.He also explains Japan has beenchosen as the testing centre for the taxis.92 percent of the population in Japan live in towns andcities,and Toky e of the mostes in the world.These make Japan a grearplace 7 torunthe tests,he says.The president of ANA is excited ahouteproject.He says,"ANA has about 70 years ofexperience in delivering flights gasfe).Being able to provide this rapid and sustainable way oftransport for customers 10(be)attractive and encouraging."卷（五）·英语·第2页（共2页）》

秘密★启用前韶关市2023届高三综合测试(二)英语本试卷共10页，卷面满分120分。考试用时120分钟。注意事项：1.答卷前，考生务必用黑色字迹的钢笔或签字笔将自己的姓名、准考证号和班级填写在答题卡指定的位置上。2.选择题每小题选出答案后，用2B铅笔把答题卡对应题目的答案标号涂黑。如需改动，用橡皮擦干净后，再选涂其他答案。写在本试卷上无效。3.非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡指定区域内的相应位置上；如需改动，先划掉原来的答案，然后再写上新答案；不准使用铅笔和涂改液。写在本试卷上无效。4.考生须保持答题卡的整洁，考试结束后，将本试卷和答题卡一并交回。第一部分阅读（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。AStaying at home and watching Netflix is quite cozy.To help you figure outwhat to watch,we take a dive into the collection and list some options releasedin the last year or so that are well-worth a watch.Penguin Bloom (2021)95 mins,directed by Glendyn IvinNaomi Watts stars in this emotional roller-coaster of a film about a womanstruggling to recover from a catastrophic injury.After her children bring homean injured bird,her character's efforts to nurse the magpie nicknamed "Penguin"back to health unfold in parallel with her own healing journey.Metal Lords (2022)97 mins,directed by Peter SollettJaeden Martell and Adrian Greensmith play a pair of teenage friends whodecide to form a heavy metal band and enter their high school's Battle of theBands competition.What they don't expect,however,is to have their friendshiptested and to learn a lot more than about music when they recruit a shy cellistto join them.The Sea Beast (2022)115 mins,directed by Chris WilliamsChris Williams directs this animated high-sea adventure about a young girlwho boards a famous monster-hunting ship secretly,only to discover thateverything she thought she knew about monsters and hunters might be wrong.英语测试题第1.页（共10页）

21.（12分)解：（1)乙、丙、丁三人每次接到传球的概率均为二，3次传球后，事件乙、丙、丁三人均接3过传出来的球发生的概率为B=店×（付=2…3分(2)由题意知，X的可能取值为1,2,3，PX==3x=)PX=3)=Ax-号PX=2=1-P(X=)-PX=3)=.6分X的分布列如下：X123P1-92-32-9.7分EX)=1x+2x2+3x2=199.8分399(3)证明：n次传球后乙、丙、丁三人均接过他人传球，有两种情况，其一为：n-1次传球后乙、丙、丁三人均接过他人传球，这种情况的概率为P:其二是为：n-1次传球后乙、丙、丁中只有两人接过他人传球，第n次传球时将球传给剩余一人.这种情况的概率为0-P-3×)×兮9分3所以，当n≥4时，Pn=P+(1-Pn1-3×111.P、一。iP11分12分3322.（12分)解：(1)a=l,f(x)=e-lnx,x>0因为f"(x)=e”--,f"(I)=e-1,…l分因为f()=e-lnl=e,即切点为（山，C)…2分f(x)在点(L,)处的切线方程为：y=(e-1)x+1…3分(2)证明：因为f树）=ae-(a≥x>0）,…4分e设函数gx)=fa).则g'()=ae+>0(a≥x>0).e所以f'(x)在(0，十0)上单调递增…5分网为了2>0，f2定<0，所以春在Be(2ac2).使得fA=0.2ae数学答案第4页（共5页）

三、填空题：本题共4小题，每小题5分，共20分」ars d=-13.已知等差数列{.}的前n项和为S.,且a,=-1,2S,=7a,若将4，a,a,a6/0去掉一项后，利下三项依次为等比数列包}的前三项，则6为又。2a62沙新接海因14.程为)015第三届中非经贸博览会于2023年6月29日在湖南长沙举行，组委会准备安排甲2--700.51.522.53.5x乙等5名工作人员去A,B,C,D这4所场馆担任服务工作，每个场馆至少安(1)若从水库中随机捕捞一条鱼，求鱼的重量在[2.5,3.5]内的概率；排1人，其中甲、乙不能安排在同一场馆，且乙不能安排到A场馆，则不同的安C2(2)从捕捞的100条中随机挑出6条鱼测量体重，6条鱼的重量情况如表：排方法种数为82叱22重量范围（单位：kg)[0.5,1.5)1.5,2.5)[2.5,3.516.正三棱柱ABC-AB,C的底面边长是4，侧棱长是6，点M,N分别为CC,AB的条数13中点，若点P是侧面BCCB,上一点，且PN∥面AB,M,则线段PN的最小值为22①为了进一步了解鱼的生理指标情况，从6条鱼中随机选出3条，记随机边s1A8)污B)出的3条鱼中体重在[2.5,3.5]内的条数为X,求随机变量X的分布列和数号期望；四、解答题：本题共6小题，共0分解答应出文字说界理过政演算步果八了化05（十官资说缝石标言2条为了调整生态结构.能进种群的优化，②若将选剩下的94条鱼称重微标记后立即放生，两周后又随机捕捞1000务7.(10分况△48C的内角4.B,C约对边分别。餐动-2e…C-君)70(OC十0客福研在2：写司丙的鱼的数的4进行出告，底待算水库中鱼的2b((1)求A;losccostesincsinsV3n225a(5数以及应捕捞体重在[2.5,3.5]内的鱼的条数(2)设AB的中点为D,若CD=a,且b-c=1,求△ABC的周长3sinB=2sinAlosine.L18.(12分)正态分布有极其广泛的实际背景，生产与科学实验中很多随机变量的概率19.(12分如图，在四楼维P-ABCD中，底面4BCD为菱形，∠ABC-,PA1底面ABCDAB=PA,E是PC上任一点，AC∩BD=O分布都可以近似地用正态分布来描述.例如，同一种生物体的身长、体重等指标.随(H)求证：面EBD⊥面PAC;着人们对环境保护意识不断增强和环保工作的积极推进，环境问题得到有效解决.为了调查某水库的环境保护情况，在水库中随机捕捞了100条鱼称重.经整(2)四棱锥P-ABCD的体积为Y,三棱锥B-CED的理分析后发现，鱼的重量x(单位：kg)近似服从正布x~N么，。)，如图所体积为，者合-子求直线P9与面6D所示，已知P(x<0.5)=0.05,P(x≤1.5)=0.29成角的正弦值卷第4页L05A)广+(5升-COSA-数学试题卷第5页共6页3C05闪千Uo2

to promtethe law to 59 against people on the grounds of mental illness I added,"Compulsory ad-public acting as major performers,is aimed70(promote)rural art,culture and tourism,"mission to hospital under the Mental Health Act is intended to have 60 consequences forsaid Zou Fuqiao,an official of the Culture.Touris Radio.Film and Sports Bureau of Jiangtheir life,not negative ones."Luckily,what I said dawned on them,and Melissa got goodhua Yao Autonomous County.treatment第四部分写作（共两节，满分35分）P)41.A.determinedB.anxiousC.astonishedD.sure第一节短文改错（共10小题：每小题1分，满分10分）b2.A.wards项片B.countersC.officesD.cafeteria假定英语课上老师要求同桌之间交换修改作文，请你修改你同桌写的以下作文。文中共有43.A.examB.illnessC.careerD.safety10处语言错误，每句中最多有两处。每处错误仅涉及一个单词的增加，副除或修改。44.A.protestB.approveC.pronounceD.applaud增加：在缺词处加一个漏字符号（Λ），并在其下面写出该加的词。5.A.laughedB.teasedC.compromisedD.begged删除：把多余的词用斜线（小）划掉。A46.A.carefreeB.happyC.strickenD.impolite修改：在错的词下划一横线，并在该词下面写出修改后的词。47.A.billsB.advertisementsC.newspapersD.notes注意：山，每处错误及其修改均仅限一词；48.A.contentB.stressedC.pleasedD.familiar2.只允许修政10处，多者（从第11处起）不计分。49.A.abuseB.depressionC.violenceD.injusticeWhen I woke up this morning,but I heard the sound of rain outside.I told to myA50.A.desiredB.agreedC.hesitatedD.failed,andmother at once.Mom said she had heard it.either.But she felt it was strange as there wouldA 51.A.checking1B.bringingC.tyingD.pickingD52.A.noddedB.changedC.comprehendedD.refusedbe no rains according to the forecast.We went to the window to have a look.There turned53.A.favourB.propose('opposeD.direct亿54，A.regardless ofout that an upstairs neighbor's solar water heater is overflowing.The neighbor must have hadB.free ofC.in case ofD.on account of55.A.investigateB.apologize('understandD).Improvethe tap turning on.but forgot to turn it off in time.So I went out and knocked the neighbor'sB56.A.adviceB.future(.identityD.appearanceB7.A.alwaysB.never('hopefullyD.potentiallydoor.Then I told the neighbor that had happened to her heater.She was gratefully to me be-么8.A.mparB.property(investmentD.benefitcause my action prevented her from waste much more water.C59.A.voreB.insure('fightD.discriminateCAearnnB.impossible('positiveD.temporary矧线第二节书面表达（满分25分）解第二节（共10小题：每小题1.5分，满分15分）假定你是校英语俱乐部负责人李华，请你给外教Joh如写一封邮件邀请他做一次关代英语阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。学与英语文”的讲座，内容包括：A report showed that a crowd of 61 (resident yof Jianghua Yao Autonomous County,1.讲座的时间和地点：Hunan Province.62 (singand danced on Saturday fo celebrate the coming of Jingzhe or2.讲座的对象和内容。the Awakening of Insects.The event 63 (ao people exhibiting their grand tra-注意：ditional costumes.singing folk songs.performing tai chi and dragon dances and dancing on1.词数100左右：Engb3hanpaddle boards or boats.impreppedtourists with the unique Yao culture.2.开头和结尾已为你写好。Lerin EnJingheis the 64 (thre solar term of the 24 terms 65 (define)by the tradi-CQclturptional Chinese calendar.It falls on March 6 and ends on March 20 this year,which means660 sharp rise in temperature and increased rainfall.The name suggests animals sleeping in一7winter 67 (awaken)by spring thunder.For farmers,it becomes a termt憾marks thestart of spring work.It is the best time for farmers to sow.so they will be busy in order tohave a harvest in autumn."The event,69 the natural landscape serving as the stage and the members of the·23-426C·【高三英语第9页（共10页）】·23-426C·【高三英语第10页（共10页）】

21.(本小题满分12分)如图，在四棱锥P-ABCD中，△ABD是边长为2的正三角形，BC⊥CD,BC=CD,PD⊥AB,面PBD⊥面ABCD(I)求证：PD⊥面ABCD:(2)若PD=1,求二面角C-PB-D的面角的余弦值.22.(本小题满分12分)已知函数f(x)=2-2,g(x)=log2x.()若对任意的x∈(0，)，f(8(x)

2W5在RAKB中，cos∠BKA=6BK2W3065所以面C与面，ADF所成锐二面角的余弦值为5(方法二)由(2)知ED⊥面ABCD,且AD⊥CD.以D为原点，DA,DC,DE所在直线分别为x,y,轴，建立空间直角坐标系易得B(2,2,0),C(0,4,0),E(0,0,2).面ADEF的一个法向量为m=01,o).设n=(x,y,)为面BEC的一个法向量，因为配=(220，正=04所以20令=1，得)=-2.所以n=(11,2)为面BEC的一个法向量.设面BEC与面ADEF所成锐二面角为O.m1则cos0=。所以面C与面0F所成锐三面角的余弦值为网同66考点：中位线、行四边形的证明、线面行、线面垂直、面面垂直、二面角21.（1)an=(n+1)2",n∈N;（2)证明见解析（1)由s,=2a-2，推得号-==1，得出数列{受表示首项为2，公差为1的等差数列，进而求得数列的通项公式；(2)由题意，求得。-2”，根据2”京>)，得到公分之a≥2，进而证得无<后手，再由”=1时，得到<手，即可得到结论（1)由题意，当n=1时，可得S=2a-4,解得a=4,又由Sn=2an-21,当n≥2时，Sn1=2an-1-2”,两式相减，得a,=24-2a-2,即0，-24=2，可得2-=-1，又由？=2，所以数列}表示首项为2，公差为1的等差数列，所以=2+(n-)=n+1,所以a,=(n+2,n∈N。

B.k∈-00,eC.当k<0时，x+x2<1D若f(x)=k的根记为x,:,g(x)=k的根记为x,x4,且x<<0,w>0,x∈[0,8]）的图像，且图像的最高点为S(6,4V3),绿道的后一段为折线段MNP,且∠MNP=120°（如图所示）.y0(6.0)(8.0)P(16,0)x(1)求实数A和ω的值以及M、P两点之间的距离；(2)求△MNP面积的最大值18.(本小题满分12分)如图，在棱长为A的正方体ABCD-A,B,C,D,中，M,N分别是AA,CD中点，过D,M，N三点的面与正方体的下底面AB,C,D,相交于直线1.

讲三步一体高效训练记Marggraf as director of the Berlin Academy of Sciences.Instead,shying from politics,he chose sim-ple surroundings so that he could work without jealousy or evil intention in his own pharmacy labo-ratory.He was born in Stralsund,Germany,at that time Swedish Pomerania.His parentage wasGerman,and throughout his life he used this language to write down his laboratory notes.He re-ceived an excellent education and experienced an enjoyable childhood painting and collecting insectsand plants.At home he was particularly fascinated with the conversations of the friends of his par-ents,who included doctors and pharmacists.He fell in love with pharmacy books.From borrowedtextbooks of chemistry and pharmacology he devoted himself to absorbing all possible knowledge onthe subjects.He performed over 13,000 experiments in his lifetime,but only a few pieces of laboratory notesand correspondence exist.With his incredible memory Scheele committed virtually everything tomemory and he wrote little.He drove himself constantly,laboring every evening in his laboratory af-ter performing his daily work as a pharmacist.Sir Humphry Davy said of him,"Nothing could dampdown the passion of his mind or chill the fire of his genius:with very small means he accomplishedvery great things..”11.What does the first paragraph mainly tell us about Scheele?A.His short career as a pharmacist.B.His devotion to his work.C.His poor working conditions.D.His achievements in chemistry12.What can be inferred about Scheele?A.He was good at photographing.B.He was admired by his colleagues.C.He cared little about personal fame.D.He preferred to work alone in the lab.13.How did Scheele perfect his knowledge of pharmacy?A.His parents taught him a lot at homeB.He attended a famous medical school.C.He learned from recorded conversations.D.He taught himself through relevant books.14.Humphry Davy's comment is mainly about Scheele'sA.unusual way to conduct experimentsB.extraordinary memory for notesC.passion for and devotion to chemistryD.daily routine working in the lab【答案与解析】本文介绍了瑞典化学家和药剂师Carl Wilhelm Scheele在化学及药剂学方面的研究及成就。ll.D通读第l段可知，本段主要介绍了Carl Wilhelm Scheele在化学研究方面所取得的成就。12.C根据第2段最后两句可知，他曾经拒绝了担任柏林科学院院长的提议，并选择了简单的环境以便继续他的研究。因此，我们可以推断出Carl Wilhelm Scheele不太在乎个人名誉。13.D根据第3段最后两句可知，他爱上了药学书籍，专心致志地从借来的化学和药理学课本中自学与这些学科有关的知识。l4.C根据最后一句可知，Humphry Davy这样评价Carl Wilhelm Scheele:“没有什么能浇灭他心中的激情，也没有什么能熄灭他在化学上的天才之火：他用非常简陋的设备做出了非常伟大的贡献。”因此，Humphry Davy评价了CarlWilhelm Scheele对化学的热爱和奉献。【24新教材，ZCYK,英语-BSD-选择性必修第二册-Y】

10.ABDf(x)=2r的定义域与值域均为(0，十∞)；f(x)=log2(Wx十1)的定义域与值域均为[0,十)：)-之的定义域为(-6,0U0,+e∞)，值域为0，十∞)：/)-号的定义域与值域均为（一∞，7）U(7,十∞.11.ACD因为M~N(250,o2),所以P(M>249)=P(M<251)=0.75,A正确.因为P(M<251)=0.75,所以P(249253)=0.75-0.7=0.05,若从该阿胶产品中随机选取1000盒，则质量大于253g的盒数X~B(1000,0.05),所以D(X)=1000×0.05×(1-0.05)=47.5,C正确.P(2510，阳=一录，所以直线AP与直线BP的斜*之差为及十≥2√日=号，当且仅当69,即k=}时，等号成立，所以直线AP与直线BP的斜率之差的最小值为号，B错误直线AP的(x-3),则N的坐1方程为y=k(x十3)，则M的坐标为(5,8k).直线BP的方程为y=35-V105标为6，)，所以MN1-√P+(8+≥√1-(2V8k·P-√3当且仅当k=京即=得时，等号成立，所以M1N的最小值为C正确设函数)√12+(8k动)-√161)(>日).则f)为增两数，所以f)>(专)=/9+2=30,因为C<2=23宽，所以D错误933331.该等差数列的公艺d号号3-214,7an8月计3x2an8Ha》3321.故am8计a产7tan(B-a)15.0.145433由全概率公式可得所求概率为0.1×4十3+3+0.2×4十3+3+0.15×4+3十30.145.【高三数学·参考答案第2页（共6页）】·24-29C·

则下列结论正确的是()n2+n+2A.a,=nn∈N)B.a0=5C.a,a4,as成等比数列D.4+42++am=411.下列四个命题中，错误的是()A.“m≤1"是“关于x的方程m2+2x+1=0有两个实数解的必要不充分条件B.命题“x∈R,使得+x+1<0"的否定是：“对x廷R,均有x+x+1>0”y=Vx2+2+1C.若x>0,则函数√2+2的最小值是2D.若函数.f()=x+3ax+br+a在x=-1有极值0，则a=2,b=9或a=1,b=3.12.已知￥，名分别是函数f)=e+x-2和8()=lnx+x-2的零点，则()A.+X2=2ex+Inx2 =22ve2D.+好<3三、填空题：本题共4小题，每小题5分，共20分.13.数列{a}中，4=2，a1=20,n∈V*.若其前k项和为126，则k=cosπ，00时，f(x)>0,f(k2)+f(41-8-2)>0对任意X∈[1,2]恒成立，则实数k的取值范围是2216.函数f()=r-ax血r在e上不单调，则实数a的取值范围是试卷第3页，共6页

20.（本小题满分12分)如图，在四棱锥P-ABCD中，底面四边形ABCD为直角梯形，AB∥CD,AB⊥BC,AB=2CD=2BC,O为BD的中点，BD=4,PB=PC=PD=√5.(1)证明：OP⊥面ABCD;(2)求面PAD与面PBC的夹角的余弦值.21.(本小题满分12分)已知直线l:(2m十1)x-(3+m)y+m-7=0.(1)m为何值时，点Q(3,4)到直线1的距离最大，并求出最大值；(2)若直线1分别与x轴，y轴的负半轴交于A,B两点，求△AOB(O为坐标原点)面积的最小值及此时直线（的方程.22.(本小题满分12分)如图，在直三棱柱ABC-A1B1C1中，AC⊥BC,AC=BC=AA1,D为A1B1的中点，G为AA1的中点，E为C1D的中点，BF=3AF,点P为线段BC1上的动点（不包括线段BC的端点).(1)若EP∥面CFG,请确定点P的位置；C(2)求直线CP与面CFG所成角的正弦值的最大值.AGB【高二数学第4页（共4页）】24139B

综上，实数a的取值范围为(-∞，-1]U[0,1].10分18.解：(1)由题意可知，关于x的不等式x2-(a十b)x十2a<0的解集为{x10,即(x-a)(.x-2)>0,…6分当a<2时，解得x2;当a=2时，解得x≠2；当a>2时，解得x<2或x>a.…10分综上可知，当a<2时，原不等式的解集为{x|x2};当a=2时，原不等式的解集为{xx≠2}；当a>2时，原不等式的解集为{xx<2或x>a}.……12分1解：1因为g)=四-（告）广-（会）广，且g)十g-)=0,所以告-号，解得a=士2，又a>0,故a=2√2.…4分(2)由1知g()=2)-(号)广，[g(x)P=2r+2-2,则f)+[g=十2-2.…6分令t=2r∈(0，+∞)，则h(t)=fx)+[g(x)]2=2+1-2,N()=2}2己，令N()=0,得1=2，当(0,2)时，N()<0,A()单调递减：当∈2(2,十o∞)时，h'(t)>0,h(t)单调递增.…9分所以当=2寸，A()取得最小值(2)=3×2号-2.即x=一号时，fx)十[g(x)的最小值为3×2-2.…12分20解：1由f)=号x2+ax2+6x,则f()=2+2ax+5,因为x=3时，f()取到极值，所以广(3)=0，解得a=一52·2分又当a=-时，f(0=2-5x+6=(-2)(3).当x<2时，f(x)>0,当23时，f(x)>0,故当x=3时，函数y=f(x)取得极值，符合题意.…4分要使f(x)在(m,m十2)上为增函数，则m十2≤2或m≥3，所以m≤0或m≥3.即实数m的取值范围为(-∞，0]U[3,十∞).…6分(2)令A()=f(x)十m,1得)=合r-号r+6,且13，故A(x)-3r-号r+6x+ml0,解得1

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三、填空题：本题共4小题，每小题5分，共20分。18设p:3m1w>2-1.则p是n252m14函数/心)--g的定义城为C1,2]重UC0,)1-2-x1点若命题3r∈[0.3]2-2r9<0为假命题，则实数的取值范周是a(日xeo,3x2X-A2016已知系数)品则不等餐2，智备解第是{a刻o四、解答题：本题共6小题，共70分。解答应写出文字说明、证明过程或演算步骤。17.(本小题满分10分)(RB-CxIx3成)6328已知集合A=(x(x+2)(8-x)≥0)，B=(x-3≤x<6)a求AU(tB,-2X利2成8-36(2)若C={xm+1≤x≤2m-1),C(A∩B),求实数m的取值范围.b女七mH17,3-3268土斤2444272七士2)21im18.(本小题满分12分)2ml已知函数f(x)-2x十2·(1)判断f(x)的奇偶性，并用定义证明；士真啦A合A（2)判断/)在区间(0，号)上的单调性，并用函数单调性定义证明，县帕能面分宗收不.(本小题满分12分)设函数y=ax2+(b-2)x+3.(1)若不等式y>0的解集为{x一14的解集：0(2)若1=1时，y=2,>0,6>0,求}+号的最小值07+bx3)0(c0b-2>0132203b-4a:-【高一第二次质量检测卷·数学第3页（共4页）】241260Z

7.已知函数f(x)=(2a-3)x十2，x≤1，完文出官血搭缩。0共，服>1a是R上的减函数，则α的取值范围是B盛若飘烟代GA0a欣后1

MA=MEMA=MB设球心为M(x,2,则M4=MC3V282=x23v2V=823W2-28可得解得R=MA32V2+2×32√388288所以，三棱锥E-ABC的外接球半径为W384元R2=4元×19π因此，三棱锥E-ABC的外接球的表面积为8819元故答案为8四、解答题：本大题共6小题，共70分，解答应写出文字说明，证明过程或演算步骤.1n+13.01-17.已知数列a,的前2项的和为S,且4方a3nan(1)证明数列n了是等比数列，并求a,的通项公式：(2)求数列a,}前n项的和Snnan=【答案】(1)证明见解析，3"32n+3(2)S.=4439【解析】an【分析】(1)利用等比数列的定义可证得结论成立，确定等比数列〔”J的首项和公比，可求得数列{a}的通项公式：(2)利用错位相减法可求得S,第15页/共23页

所以a,=2+2(n-)=2n.4044404,440444…4……5分(3R-H)HR(后2)由D知，6，-3a,-2nx3,…6份…7分3R-H2)H3-后则T,-2X1X3°+2×2X3++20n-)×3242n×3-,故3T=2X1X3+2X2×32++201-1)×3-1+2n×3”,………8分两式相减得，-2T=2+23+…+3--2n×34………………9分近线方程为bx-a=0,可得R,到=2+2×30-3-2nx31-3…10分b.1R=2e.由∠R有=-1+(1-2n3",…………11分所以渐近线方程为y=士2x所以z2,…12分+2×3"19.(本小题满分12分)(1)证明：，∠BDC=60°，BD=2CD=2,则由余弦定理得BC2=BD2+CD2-2BD·CDcos∠BDC=3,…分sinA,…1分2分则BD2=CD2+BC2,即BC⊥CD,.3分…一2分面PCD⊥面ABCD,…4分…3分且面PCDn面ABCD=CD,…5分BCC面ABCD,……4分.…6分∴BC⊥面PCD.……5分(2)如下图，因为PC⊥面ABCD,PC=√3，……6分BC⊥面PCD,AB=BD=2CD=2,7分………7分故以CD,CD,CP所在直线分别为x,y,z轴建立空间直角坐标系，一8分则AW5,2,0),D0,1,0,P0,0,N),DA=(W5,1,0),DP=0,-1,5),…8分设面PAD的法向量为m=(x,y,………9分DA·m=0,[5x+y=0,由得取y=3,得x=-1,z=l,…10分DP.m=0,y+V5z=0,!…9分m=(1,√5，)，10分…1分易得面PCD的一个法向量为n=(1,0,0),…2分..(cos(m,n)=m·n15…l1分……3分…12分…4分,面PAD与面PCD夹角的正弦值为，数学参考答策及评分标准第4页（共6页)【202.4广西夕校米-)1

第20期B1版Keys:(One possible version选择题除外)阅读训练营1-5 BBCBD完形小测1-5 CADBA6-10 CDBAC非常解读1.spend2.dead3.excited4.latest5.talking6.of7.suddenly8.paid9.means10.best第20期B2版Keys:(One possible version)知识串联【运用】1.go over2.try out for3.lose heart4.change your mind5.broke into写作一招鲜I want to be a farmerI want to be a farmer when I grow up.Maybe you will laugh at me.Let me tell you thereasons.Firstly,I like plants and animals.And I am good at biology and science.Secondly,foodsafety is a serious and important problem now.So I want to plant healthy vegetables and fruitthat are good for people's health.In order to know more about plants and animals,I need tostudy hard and go to a college.One day,I'll send people some vegetables and fruit instead ofsome medicine.People will have a healthy life!第20期B3版Keys:(One possible version)词语狙击抛砖引玉1.somewhere2.traditional3.praise4.bell1/3

B.To study sea creatures. C.To study traditional artworks. 19.What do most people of Bali do? A.Work in tourism. B.Do agricultural work. C.Produce special machines. 20.What does the speaker suggest doing especially during Chi- nese New Year? A.Drinking organic coffee. B.Doing some shopping. C.Visiting Buddhist temples.

A.will have been B.have been C.were D,would be 10.There has been positive reaction to the proposal of helping the dis- abled,the impact will be lasting especially for younger ones. A.on which B.on whom C.of which D.of whom 11.Scarcely myself comfortable and closed my eyes when I heard the sound of the alarm. A.I got B.I had got C.did I get D.had I got 12.A great deal of hotel business comes from people travelling not just for holidays but by people travelling their

ment in the brain,where memories are formed.Even though re- laxing music can be effective,silence is ideal. 38 When sur- rounded by pure silence,your consciousness has more freedom to process information.This can lead to better decision making and more acute self-awareness. 39 A recent report suggested that one in three people lose a whole year off their life due to noise.And this is linked to heart disease,sleep loss and high blood pressure. Although many find silence to be empty and boring,it is a gift and a rare thing like gold.40 When you welcome it and let it fill you,you are open to healing and wellness. A.Silence assists in self-healing. B.Silence can generate brain cells.

says about you. G.You must have a good car,so you can travel to different parts of the country.