3.(分析景物、环境特点)“江城五月落梅花”一句的景物描写有何特点？请简要分析。[思维训练]弄清诗（词）句所写景物一阐述景物特点一分析诗人情感(1)“江城五月落梅花”中的“江城”指的是,所写到的景物是(2)诗句中的“梅花”是“五月”的梅花，“五月”是仲夏季节，而“梅花”是寒冬之景，所以这句诗是写，是由笛曲《梅花落》想到的“落梅花”。(3)“江城五月落梅花”通过“梅花”和“五月”两个看似矛盾的事物，写出了诗人的情感。[方法归纳]1.弄清诗（词）句都写了哪些景物2.概括出所写景物的特点，如荒凉、凄清、萧瑟、艳丽等。3.从景物的特点入手进一步分析诗（词）的情感。4.从表现手法角度分析写景的妙处，如寓情于景、借景抒情、动静结合等。答题模板]这句诗（词）描写了…景物，运用了…手法，表达…的情感。4.(赏析写作手法)诗歌的第三、四两句运用了什么表现手法？有什么作用？思维训练]准确指出用了何种手法一结合诗句阐释如何运用这种手法→分析手法所产生的表达效果(1)这两句诗由听到的联想到,形象具体地抒发了诗人满怀凄凉之情。(2)诗人借助梅花纷纷飘落的景象，抒发了去国怀乡的愁绪，运用的是的手法。(3)判断正误。①第三、四句点题，写在黄鹤楼上听笛声，由笛声联想到梅花飘落的苍凉景象，前后情景相生，妙合无垠。(②这首诗艺术结构独特，写听笛之感，并没有按闻笛生情的顺序去写，而是先有情，而后写闻笛。()[方法归纳]1，从修辞手法角度分析。首先判断诗词使用了何种修辞，然后结合诗（词）句阐释怎么用的、为什么用这种手法，最后分析此手法怎样有效传达了诗（词）人怎样的感情。2.从表达方式角度分析。鉴赏时要准确指出诗（词）中运用的表达方式，然后结合诗（词）句和具体词语进行分析。分析时要指出这种表达方式表现了什么内容，抒发了什么样的思想感情。3.从表现手法角度分析。分析时，抓住诗（词）句最突出的手法来分析，如借景抒情、动静结合、虚实相生、欲扬先抑等。答题模板]这句诗（词）运用了…，表达了…，抒发了…。5.(分析思想感情)这首诗抒发了诗人怎样的情感？3

湖北省黄冈中学2023届高三第三次模拟考试数学试卷命题教师：钟春林夏泊凌庄四化审题教师：钟春林考试时间：2023年5月24日下午15：00-17：00试卷满分：150分一、选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的1.设全失w=210,集合4-eN-ge-4日，则C4=()A.{-2,-1,2}B.{-2,2}C.⑦D.{-2,-1,0,2}2.已知a,b∈R,复数z=a+bi满足z(1+i)=(1-2i)2,则a+b=()A司C.-3D.-43.已知点M(1,5)在圆C:x2+y2=m上，过M作圆C的切线1，则1的倾斜角为()A.30B.60C.120D.1504.已知函数f()=2coso+1(o>0)的图象在区何0,2m)内至多存在3条对称轴，则@的取佰围是()B.c.[g5.中国救援力量在国际自然灾害中为拯救生命作出了重要贡献，很好地展示了国际形象，增进了国际友谊，多次为祖国赢得了荣誉现有5支救援队前往A,B,C等3个受灾点执行救援任务，若每支救援队只能去其中的一个受灾点，且每个受灾点至少安排1支救援队，其中甲救援队只能去B,C两个受灾点中的一个，则不同的安排方法数是()A.72B.84C.88D.1006.抛物线C:y2=2px(p>0)的准线与x轴交于点M,过C的焦点F作斜率为2的直线交C于A、B两点，则tan∠AMB=()A.25B.25C.45D.不存在57.我们打开购物台时，会发现其首页上经常出现我们喜欢的商品，这是电商台推送的结果.假设电商台第一次给某人推送某商品，此人购买此商品的概率为2，从第二次推送起，若前一次不购买此商品，11湖北省黄冈中学2023届高三第三次模拟考试试卷（共4页）第1页

496√386×√656P5=0=()(》-若49637196x25.6≈0.989，1×351P(=2)=0P(5=3)=2×写×g6由于y与x的相关系数近似为0.989，P(5=1)=1-P(5=0)-P(5=2)-P(5=3)=3,1故说明y与x的线性相关程度高.所以专的分布列为：(2)由(1)得立(x,-)(y:-)=496,含(x-刘=386，02所以6多可列37P45390≈1.28喜(x-38626.解：(1)由题得列联表如下：所以a=y-ix=92-1.28×69=3.68,男生女生合计所以y关于x的线性回归方程为y=1.28x+3.68.了解15n10n25n24.解：(1)20件产品中有5件为次品的概率f()=Co×a(1-a)5,0

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临经设函酸4罩环证阳的‘不请诺对雨约斑址·素南丫站浙秘米套#知a3日'EHL由E7n24.解：(1)x2-4x-5=(x-2)-9……(2分)=(x-2+3)(x-2-3)(4分)=(x+1)(x-5)（2）-23=-242)+3-2(+21)+3+2=-2(+1025，…(6分）(x+1)2≥0.-2(x+1)2≤0，即-2(x+1)2+5≤5，当=-1时，多项式-22-4+3有最大值，这个最大值是5.…(8分)25.解：(1)设甲、乙两种图书每本的进价分别是x元、(x+20)元，则540.780xx+20…(3分）解得x=45，检验：当x=45时，x(x+20)0,:x=45是该方程的解，且符合题意.x+20=65.甲、乙两种图书每本的进价分别是45元、65元…(5分）(2)设购进甲图书m本，则45m+65(70-m)≤3550，…(7分)解得m≥50，至少购进甲图书50本…(8分）26.(1)证明：在口ABCD中，点0是对角线BD的中点，.AD∥BC,B0=D0.∠ADB=∠CBD.·∠BOE=∠DOF.△BOE≌△DOF(ASA)…(2分)DF=BE.DF∥BE四边形BEDF是行四边形(4分(2)①解：如图2，过点D作DN⊥EC于点N,DE=DC=√I0,DN⊥EC,CE=2,EN=CN=1.DN=vDc2-CN2=3........................(5分∠DBC=45°，DN⊥BCE N.∠DBC=∠BDN=45°BN=DN=3.BE=BN-EN=3-1=2.②证明：DN⊥EC,CG⊥DE…(7分).∠CEC+LECG=90°，∠DEN+LEDN=90°∠EDN=∠ECGDE=DC,DN⊥EC∠EDN=∠CDN,·.∠ECG=∠CDN∠DHC=∠DBC+∠BCH=45°+∠BCH,∠CDB=∠BDN+∠CDN=45°+∠CDN…(9分),∴.∠CDB=∠DHC.CD=CH……(10分)八年级数学试题答案第3页（共3页）

7.已知a,b为实数，则a>万"是b士>b”的a+laA.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件8已知a>0,6>0,且a+6=2,则。+6的最小值为A.2B.3C.4D.59.在数列{a}中，a1=2,且点(am,a+1)在函数y=x2十x的图象上，则A.Vn≥2，n∈N,an≥2X3m-1B.Vn≥2，n∈N,am≥2X3"C.Vn>2,n∈N,am≥2X4"-1D.Hn≥2，n∈N,am≥2X4"10.设(1-2x)0=a十a1x+a,x2+十aox,则2na.=n=1A.-20×39B.20×39C.-20D.2011.某市中心医院派出甲、乙等5名医生去A,B,C,D四所学校做流行病预防宣传，每所学校至少派1名医生，每名医生必须去一所学校，若甲不去A学校，乙去B学校，则不同的安排方案有A.24种B.36种C.42种D.48种12.已知实数a,b,c满足asin0.01=0.01,be=1,c=cos0.2,则B.c

第二章函数第2课时奇偶性与周期性⊙答案见515页基础达标练8.写出一个同时具有性质①②③的函数：f(x)=1.下列函数既是奇函数，又是增函数的是A.y=l0g3 IxlB.y=x+2x①f(x)是定义域为R的奇函数；C.y=e*D.y=x-3②f1+x)=f(1-x);2.(2023山东济宁高三一模)定义在R上的奇函数③f1)=2.fx)满足f(x-2)=-f(x),则f(2024)=(9.(2022山东枣庄高三一模)已知函数f(x)=ln(e“+A.0B.1C.-1D.20221)-x是偶函数，则实数a的值为10.(2022广东湛江模拟)已知函数fx)是定义在R上3.(2020全国.0,5分)设函数(x)=女则x》的奇函数，当x∈(0，+∞)时，fx)=x2-x-1,则当xe(-0,0)时，f(x)=A.是奇函数，且在(0，+∞)单调递增能力强化练B.是奇函数，且在(0，+0)单调递减11.多选题(2023江苏扬州高三模拟)已知函数f(x)是C.是偶函数，且在(0，+∞)单调递增定义在R上的奇函数，f(x+1)是偶函数，当x∈[0，D.是偶函数，且在(0，+∞)单调递减1]时，f(x)=x2+x,则下列说法正确的有（)4.(2023河北秦皇岛高三三模)设偶函数f(x)在(0A.函数f(x)的图象关于直线x=1对称+)上单调递增，且f(4)=0,则不等式f(x)f-x)B.函数f(x)的一个周期是42x<0的解集是(Cf2023)+f(2024)=0A.（-4,4)B.(-4,0)U(0,4)D.方程f(x)=IIn x恰有4个不同的实数解C.(-4,0)U(4,+∞)D.(-∞，-4)U(0,4)12.(2022新高考Ⅱ，8,5分)已知函数fx)的定义域为5.设定义在R上的函数f(x)的图象关于直线x=1对R,且f(x+y)+fx-y)=f(x)f(y),f(1)=1,则称，且当a1时=h-1,则兮)，)三n()A.-3F(侣)的大小关系为B.-2C.0D.1ar)y)()13.(2023山东聊城高三模拟)若函数f(x+2)为偶函数，Hx1,x2∈[2，+∞)，且x1≠x2,都有(x1-x2)·r()([fx)-f(x2)]<0,则cr()A.f(log26)0时，x)=6,则f)三R:A.-21B.-22C.-23D.-24·277

h,=(1,0,5…10分且PC=(-1,2√5，-V3)所以cs,-同武1所以直线PC与面C所成角的正弦值2.…12分20.(1)设多选题正确答案是“选两项为事件4，正确答案是“选三项”为事件4，则2=AUA.考生得0分，2分为事件B,B2,P(4)=P,p(A)=1-P.因为B。=A,B。UAB。,所以P(B)=P(A,B。UAB。)=P(A,B。)+P(AB。)=P(BA)P(A)+P(BA)P(A)2C4488…2分因为B2=A,B2UAB2,P(B2)=P(4B2 AB2)=P(4B2)+P(4B )P(B2 P(A2)+P(B A)P(A)L×C+LxCg-=2+2*C8…4分所以，得分X的分布列为：X05P388355得分X的数学期望E(X)=0×二+2×二=…6分884(2)方案一：随机选择一个选项正确答案是“选两项时，考生选1项，选对得2分，选错得0分：正确答案是选三项时，考生选1项，选对得2分，选错得0分.因为B。=A,BoA Bo,211,1所以P(a,)=P(B,4)P(4)-P(a,4)P(4)-=A×年+1-P)×子4+4P:因为B2=A,B2UAB2,第3页共12页

@影县⊙州螺讲评三步一体高效训练札记灯y=log(x一5)一8，(a>0,a≠1)的图象恒过定点A,若点A在角0的终边上，期A虹三、解答题：本题共2-号9.(18分)已知关于x的方程c(1)若cos0≠0，求D.号(2)若>0，求k的解析：因为关于x的解析：对于面数)=1b吧红一5)-80>0，a≠1D,令x一-5=1，求得x=6,y=一8，可得定点A6,-8).国为点A生(1)因为cos0≠0，所角0的终边上，可得cos0=6-,sin0=8(2)由sin0+cos0√62+(-8)又k>0,所以k=1.答案：A10.(18分)6.(多选题)已知sina十cosc=sin a-cos a3,00,cosa<0,进而得sina-cosa>0,故B项错误；因为sin'a-cosa=(sin'a-cos'a)(sma-2)-13(-号)2+1弓，故C项正确；因为1-2 sin2sin a-cos'a(sin a-cos a)2sin a-cos a(sin a-cos a)(sin a+cos a)sin a+cos a=一3，故D项正确.答案：ACD二、填空题：本题共2小题，每小题8分，共16分7.已知角a的终边经过点P(sin8,cos0》,若cosa=},则sin0=解析：点P(sm8.os)到厚点0的距离OP=V于o0-1,则cosa=8别=sn0-子答案：号8.公园内有一个等边三角形的花坛，沿着三角形花坛一边的中线把花坛分为三角形A和三角形B,用以种植不同的花如果三角形A的三个内角的正弦之和为S,三角形B的三个内角的余弦之和为解析：由题意知，三角形A的三个内角货次为30,60,90，三角形B的三个内角依次为30,60,90则5m30+m60+m0专十号+1，o930十co60中o9o=9+号+0=E所以号22答案：√350【24新教材，ZC数学-RA-必修第一册-GDONG】

全国C0所名校高考模拟金典卷解颜桥设OO,∩EF=D,由题意得Rt△ObFD∽R△O,ED,所以88-8器=分.41an=,0-23(1O2D1+1OD1=/3所DE=√2型)-4=号1DF=√-1=号，3所以2c=|DE1+DF1=2(c为椭圆的半焦距)，得c=1.设直线E下与圆锥的一条母线相交于点A,圆锥的母线与球O、球O2分别相切于B,C两点，如图所示，则|AB=AE1,ACl=AF,两式相加得IAB+|AC=AE引+|AF=a-c十a+c=2a(a为椭圆的长半轴长)，即1BC1=2a,过点O2作O,G⊥OB,垂足为G,则四边形BGO2C为矩形，房以2=C=0G-B=2,得a=厅，所以精图药离心率为后-号16.如图，在棱长为2的正方体ABCD一A,B,CD,中，P为C1D1的中点，过A,DRP两点的面a分别交棱CC1,AD于点Q,R.当R为A,D的中点时，A,面。截正方体所得的截面面积为;若四边形AQPR,△APR,△APQ的面积分别为S1,S,S,则惑的最小值为要号4题当R为A,D,的中点时，点Q与点C重合，面。截正方体所得的截面为等腰梯形ACPR,所以~sw=×(p+22)×3-号22以D为坐标原点，DA,DC,DD所在直线分别为x,y,之轴建立空间直角坐标系，如图所示，则A(2,0,0),C(0,2,0),A(2,0,2),C(0,2,2),D(0,0,2),P(0,1,2),则A泸=(-2,1,2).设Q(0,2,a),R(b,0,2),其中0≤a≤2,0≤b≤2，则A求=(b-2,0,2),A=(-2,2,a).设A破=mA泸+nA0(m,n∈R),即(b-2,0,2)=m(-2,1,2)十n(-2,2,a),f-2m-2n=b-2即〈m+2n=0,可得b=_404+2,(2m+an=2点Q到直线AP的距离d=√A动1：-(a西，：=5@24u+36】API3点R到直线AP的距离d=√A破1：-（巫，=压二4+8LAPI固有-马2人清山2高区质爱-享地登己13(4-a)2·APd因为0≤2，所以名。∈分，1，所以-++2=品。+号+2222+2=42【24·JD·数学（理科）-QG】48

第9期参考答案两边同时除以-3，得x=-6.情境导入：30厘米=0.3米。(2)两边同时减去号，得名？6-31设竹子x周可长到15米.两边同时乘6，得y=2.根据题意，得7x0.3=15解得x=7号3.1第2课时解一元一次方程因为x取整数，所以x≈7.所以需将“6周”中的整数“6”改为课堂探究：例(1)移项，得2x-3x=12+6.整数7.合并同类项，得-x=18,3.1第1课时等式的基本性质系数化为1，得x=-18.课堂探究：例1B(2)去括号，得4y-4=1-3y+9.例2减3-31等式的基本性质2-3移项，得4y+3y=1+9+4.即学即练：1.D2.B3.C4.C5.10合并同类项，得7y=14.6.解：(1)两边同时加上11，得-3x=18.系数化为1，得y=2.

第二部分阅读（共两节，满分50分）第一节（共15小题：每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项，There are villages and towns around the world that have fascinatingly managed to preservetheir original architecture and landscape with rapid modernization.Their rich historical contexthas led to their recognition by UNESCO as World Heritage SitesThe Old Town of LijiangThe Old Town of Lijiang in Yunnan,China,established in the 13th century,is home to theminority group-Nakhi People.The small town in southwester China still maintains its historielandscape.Its complex,ancient water-supply system is still functioning today.Vlkol f necVIkol i nec is a village that settles under the administration of Ruzomberok in Slovakia.Itmaintains more than 40 unaltered buildings from 1376.The village still hosts traditional loghouses that were once popular,,as well as the strip-shape characteristic of medieval(中世s纪的)land share.Old Town of TallinnOld Town of Tallinn dates back to the 13th century.It stands today as a preserved Medievalnorthern European trading city on the coast of the Baltic Sea.Its narrow,winding streets stillmostly keep their Medieval names,and the town wall,Town Hall,pharmacy and churchesremain in close to their original condition.The Yangdong VillageThe Yangdong Village is located in Gyeongju,South Korea.It hosts over 150 tiled-roofedand thatched-roofed homes built throughout the surrounding thick forest.There are 54 historichomes that are over 200 years old.The area's landscape,sheltered by forested mountains wascelebrated by 17th and 18th century poets for its beauty.21.What made the places World Heritage Sites?A.Architecture features.B.Rapid modernization.C.Historical context.D.Fascinating landscape22.What do VIkol i nec and Tallinn have in common?A.They share medieval characteristics.B.They are both coastal villages.C.They were made of the same materials.D.They were important trading cities.23.Which of the four sites is the youngest?A.VIkol i necB.The Old Town of LijiangC.Old Town of TallinnD.The Yangdong Village高二英语试题第3页共10页

T=≥5元-0<0339.0=验证满足条件206244:0=2或94416y=±6.·2【解析】在RM△0Qr中sin∠QF0-Y010cos∠Qr0=3vi010在aPF5中PF=|FE1cos∠OF0=3ioc,IPFl=|FEl小sin∠OFo=ioc52a=IPFI-PJ=2voc.b65a 2故双曲线的清近线方程为y=士V6一X三、解答题17.(1)n≥2时，S,m-1=an,Sn=an+1,两式相减得，an+1=2an,a2=a1=1,所以「1，n=1an=2-2,n≥2(2)n≥2时，Sn=an1，又S1=42,所以Sn=an1=2"-.18解：(1)cos24-1+c0s4b+cb222c..cos A=-+c2-d_b得b+d2=c2∴.∠ACB=90°2bc

W:He's smart.We should follow his exampleM:I agree.How about joining the beach cleanups?W:Good idea!But before that,we'd better search for some information about cleanup groupsonline.We can join a group to clean garbage together.M:OK.听第9段材料，回答第15至17题。Text 9W:Good afternoon,Sunshine Language School.M:Hello.I'd like to take an English course.Can you recommend one to me?W:Sure.What do you want to improve on?M:Although I've mastered email writing and basic daily communication,I still cannot deal wellwith giving a business speech.W:OK.We have group classes and private classes by top-rated experts.Which one do you prefer?M:Could you please tell me about the timetable?I'm afraid I can't stick to a strict learningschedule.W:Well,the timetable for group classes is fixed.Given your situation,I suggest you try ourprivate course,which will ensure that time is up to you.But such a course is much moreexpensive.M:I don't mind.I want to sign up for it now.Do I need to go in person?W:No.You just need to fill out a form on our website.If you have further questions,please call usanytime.M:OK.听第10段材料，回答第18至20题。Text 10W:Good afternoon,everyone.In today's "Reading Exchange Meeting",I'd like to share with youa book titled The Boy with Big,Big Feelings by Britney Winn Lee.The main character of the bookis in first or second grade and he experiences big feelings.Throughout the story,he is playingsoccer,playing with trucks and blocks,and chatting with his mom...all relatable things to ourstudents.What I like best about the book is that it uses pictures in the story to help recognize whatsome big feelings may look like.For example,our face may get red,we may start to cry,etc.Twomain parts of this story that my students relate to are:feeling what others may be feeling and beingworried about what others may think of our feelings.After I read this book to my students,theyrealized that we all experience big feelings and these are completely normal.This book is easy tolisten to.So I strongly suggest you read this book to your students.After you read it to them,youcan ask them many different questions about their feelings.

学不到。 31.B考查名词。作者告诉他们，这些孩子知道他们的产品不受 欢迎，但这并不意味着他们应该放弃。 32.D考查动词。根据下文qut可知答案。 33.B考查动词。如果没有人买他们的产品，或者没有人欣赏他 们的努力，可能他们下次就会放弃。 34.A考查副词。 35.C考查名词。有时候一个小小的善意的谎言也能起到很大的 推动作用。

cine, D.The advantages of animal testing were widely accepted by scientists, 35.What is the author's attitude toward the media? A.Critical. B.Favorable. C.Indifferent. D.Ambiguous.

而g(0)=0,故当xe(0,1)时，g(x)1时，令h(x)=a(1-x)cosx-1,则h'(x)=-a[co5x+(1-x)sinx],因为x∈(0,1)，则csx+(1-x)sinx>0,从而h'(x)<0,即h(x)在(0,1)上单调递减：而h(0)=a-1>0,h(1)=-1<0,因此存在唯一的xoe(0,1),使得h(o)=0,…5分并且当xe(0,x)时，h(x)>0:当xe(o,1)时，h(x)<0.即当x∈(0，x)时，g'(x)>0,当x∈(x,1)时，g'(x)<0故当x∈(0，x)时，g(x)单调递增，当x∈(xo,1)时，g(x)单调递减，而g(0)=0,放g(x0）>0;…6分取N=1-e2“e(0,1),当x>N时，g(x)=In(1-x)+asin x1时，f'(x)在(0,1)上有唯一的零点：当a≤1时，∫(x)在(0,1)上没有零点.…8分(3)10…9分理由如下：[解法一]由(2)可得，当a≤1时，ln(1-x)+asin x<0在(0,1)上恒成立即当a=1时，i血<血宝e(0,1).…10分以下证明不等式：当x∈(0，）时，有x

to like him until we ended up working in the same restaurant. He'd become a chef by then and I'd been called in to redesign the place to give it more atmosphere.The owner of the restaurant was so pleased with my work that I could have free meals there whenever I wanted them.Needless to say I became a regular though I'd have happily paid for the meals anyway.Paul's cook- ing is amazing and I'd realized that I'd changed my mind about him,too.

B.To advertise the wine country. C.To introduce some different tours. D.To suggest protecting natural wonders.

听第7段材料，回答第8至10题。 8.What does the woman probably think of the man? A.Instructive. B.Embarrassing.C.Strange. 9.What will happen after the man makes the phone call? A.He will be sent an email. B.He will receive some money. C.He will be given more information. 10.What will the man do next? A.Get on a train. B.Change seats. C.Leave for the bathroom. 听第8段材料，回答第11至13题。 11.What does the woman say about her family?

ish fluently and can understand French. (Text 5) W:So the doctor said your stomachaches are caused by too much stress? M:Yes.And he told me that I need to get positive in my daily life,adding that stress can also lead to poor sleep. (Text 6) M:Do you want to get some lunch with me? W:Sure.You mean from the coffee shop in the mall? M:I eat there every day.Let's eat somewhere else for a change. I was thinking of Romano's.And don't worry.Today it's on me.I got a reward from my boss for my good work. W:Great.That's very kind of you.We'll take my car or at least

B.Organize a trade exhibition. C.Meet the people from head office. 9.What is John preparing for the meeting? A.A report. B.A speech. C.A timetable. 10.When do the speakers decide to have the meeting? A.On June 1st. B.On June 10th. C.On June 17th. 听第8段材料，回答第11至13题。 11.Why does the woman refuse to go to KTV? A.She isn't in the mood. B.She doesn't like singing. C.She considers it a terrible idea.

15.Which is the most popular theme park with adventure rides? A.Magic Kingdom. B.Cedar Point. C.Universal Studio. 16.Which country will build the longest roller coaster? A.Singapore. B.The US. C.China. 听第10段材料，回答第17至20题。 17.Which is the best way to learn English? A.Using it frequently. B.Speaking it quickly. C.Trying to understand others. 18.What should you do when you make mistakes? A.Stop talking and ask for help.

之0之3由高污信息检测卷（全国卷）7.若函数y=(x)的大致图象如图，则(x)的解析式可能是A)D/三、解答题：共70分.解答应写出必要的文字说明、证明过程或演算步骤，第17~21题为必考题，每个试题考生都必须作答.第22,23题为选考题，考生根据要求作答。20.(12分)(一)必考题：共60分.下已知隔国C票+=1(@>6>0的左，右袋点分别为高★密17.(12分)交0已知等比数列{an}满足a1+a,=3×2”F,(-3,0),F2(3,0),且椭圆C上的点M满足(I)求数列{an}的通项公式；前小量的项，点MIMF1=号，∠M,E,=150F(Ⅱ)若数列{ab,}是公差为1的等差数列，其中b1=1,求数列{b.的前n项和T。2人0命个四不8(I)求椭圆C的标准方程；(I)若在x轴上存在一点E,使得过点E的任意一条直s暖个的年中其。而线1与横圆的两个交点P,Q都有印+0为定值，试球出此定值18.(12分)+1C=8+90<0如图，在矩形ABCD中，AB=2,BC=1,将△ACD沿AC折起，使得点D到达点P的位置，PB=√3.21.(12分)(I)证明：面PAB⊥面ABC;已知函数f(x)=2lnx+x2+x。(Ⅱ)求直线PC与面ABC所成角的正弦值（I)求曲线y=f(x)在点(1，f(1)处的切线方程；(Ⅱ)若正实数x1,x2满足f(x1)+f(x2)=4,求证：x1+x2≥2(二)选考题：共10分.请考生在第22,23题中任选一题作答如果多做，则按所做的第一题计分.22.选修4-4：坐标系与参数方程(10分)长个点零的19.(12分)在直角坐标系x0y中，直线l的参数方程为=1+31(1为参数)，以坐标原点为极点以x轴y=2-4t甲、乙两队各有2位队员共4人进行“定点投篮”比赛，规定在一轮比赛中，每人投篮一次，投中一的正半轴为极轴，建立极坐标系，曲线C的极坐标方程为p2-2pcos0-6psim0+8=0,已知直线l球得2分，没有投中得0分.现已知甲队两位队员每次投篮投中的概率均为1，乙队两位队员每与曲线C交于不同的两点M,N.次投篮投中的概率分别为Pp2,PA(I)求直线！的普通方程的一般形式和曲线C的直角坐标方程；（I)若p1=0.5,P2=04,P3=0.6,分别计算甲、乙两队在一轮比赛中得2分的概率，并根据这两个数据说明哪个队在一轮比赛中得到2分的可能性大？，代小意，小共盛本：空处，（设P1,2)求的值(Ⅱ)某同学发现：若p,=PP,则甲、乙两队在一轮比赛中得分的期望值就相等；他根据这二发2五不数可单现又得出结论：若，二P,侧在轮比赛中，按两队的均分决定胜负这两队一定是局：记23.选修4-5：不等式选讲(10分)在一轮比赛中甲队得分为5，乙队得分为”，请你写出甲、乙两队得分的分布列，对该同学的发现已知a,b,c∈R.,F分是中的量个的正确性给予证明，并简要说明该同学得出的结论是否正确。，的0,8，小内心△联9，(1若a>b>c,求证。6+6。+。。>0：11量量份民中日个或亮度来指述，(Ⅱ)若a2+b2+c2=1,求ab+bc+cm的最小值合所型8看司水小高的处和钡地应民食关曲，面量向已8量向，人门c=认，点两8，人千女收公支甘品90s.d1.5,则A与理科数学2-2（全卷共2页）B

1、衡水金卷先享题 2023届调研卷 语文(全国乙卷B)(一)1试题

清朝统治者为满族，而满族体育文化的特点之一为冰嬉，即冰上运动。乾隆帝诗《瀛台雪景》载：“每冬太液冰坚，令八旗与内府三旗简冰嬉之技”，可反映清代宫廷对冰嬉运动的重视。而蹴鞠与冰嬉的结合，则形成了清代颇

2、衡水金卷先享题 2023届调研卷 语文(全国乙卷B)(一)1试题

歌声越唱越近，渔舟在芦苇旁停住了。子胥身不由己地上了船。多少天的风尘仆仆，一走上船，呼吸着水上清新的空气，立即感到水的温柔。子胥无言，渔夫无语，耳边只有和谐的橹声，以及水上的泡沫随起随灭的声音。船到江